12x^2-18=07

Solution for 12x^2-18=07 equation:

12x^2-18=07

We move all terms to the left:

12x^2-18-(07)=0

We add all the numbers together, and all the variables

12x^2-25=0

a = 12; b = 0; c = -25;
Δ = b2-4ac
Δ = 02-4·12·(-25)
Δ = 1200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1200}=\sqrt{400*3}=\sqrt{400}*\sqrt{3}=20\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-20\sqrt{3}}{2*12}=\frac{0-20\sqrt{3}}{24}
=-\frac{20\sqrt{3}}{24}
=-\frac{5\sqrt{3}}{6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+20\sqrt{3}}{2*12}=\frac{0+20\sqrt{3}}{24}
=\frac{20\sqrt{3}}{24}
=\frac{5\sqrt{3}}{6}
$